this post was submitted on 26 Dec 2025
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No Stupid Questions

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[–] Aussiemandeus@aussie.zone 88 points 1 day ago (1 children)

The phone sends signal, that signal is sent regardless of the audio level request at the other end so the signal costs no extra energy to send.

The headphones at the other end use no extra battery from reading and interpreting the signal at different volumes.

But the energy required to make the speaker vibrate at higher rates takes more energy so the volume effects battery life.

[–] diablexical@sh.itjust.works 35 points 1 day ago (2 children)

Volume would be speaker amplitude not rates.

[–] acockworkorange@mander.xyz 5 points 18 hours ago

Higher amplitude at same frequency can only be achieved by higher rate of displacement change.

[–] PlutoniumAcid@lemmy.world 9 points 1 day ago

Potato, potahto. For an ELI5 it works well.

[–] capuccino@lemmy.world 3 points 20 hours ago (1 children)

What everyone says here make sense. But, using audio jack does use more battery, right?

[–] Wildmimic@anarchist.nexus 5 points 18 hours ago

Yup, in this case the phone sends out an analog signal, and must increase the amplitude of the signal to increase the volume, which needs more energy.

[–] Boozilla@lemmy.world 58 points 1 day ago

Phone battery=no. Wireless audio accessories like earbuds=yes. Changing digit values vs pumping air.

[–] BigBrownBeaver@lemmy.world 48 points 1 day ago (1 children)

If you make your car receiver louder, do they need to pump more energy at the radio station's antennae?

[–] sopularity_fax@sopuli.xyz 35 points 1 day ago (1 children)

—Dont hold me in Suspense—

[–] LifeInMultipleChoice@lemmy.world 11 points 1 day ago* (last edited 1 day ago) (1 children)

Not sure if you were serious, but I believe they meant, if you turn the volume up on your phone, the cell signal doesn't get worse.

The end device receives the same signal, then uses its own energy to broadcast it at whatever volume

[–] INHALE_VEGETABLES@aussie.zone 4 points 1 day ago (1 children)

Alright now riddle me this, do you burn more calories if you listen to loud sounds or quiet sounds?

[–] LifeInMultipleChoice@lemmy.world 2 points 1 day ago (1 children)

Unlike if you inhale cold /luke warm/ hot vegetables one hurts your ears more than the other

[–] INHALE_VEGETABLES@aussie.zone 2 points 21 hours ago (1 children)
[–] LifeInMultipleChoice@lemmy.world 2 points 21 hours ago* (last edited 21 hours ago)

Burns calories... But tastes delicious.

I'm one of those weird people that drinks cold water because it makes me burn more calories and im lazy... Or maybe I just like cold water more really.

[–] neidu3@sh.itjust.works 17 points 1 day ago (1 children)

No. The signal remains the same except from the bits that control the volume

[–] fizzle@quokk.au 4 points 1 day ago (3 children)

Would there be a stream of data indicating a volume setting? Or rather a once off "volume up" or "volume down" signal? My guess would be the latter but I might be wrong.

[–] toddestan@lemmy.world 3 points 1 day ago

It's the latter for all of the Bluetooth audio protocols that I've worked with.

[–] ElectricTrombone@lemmy.world 3 points 1 day ago* (last edited 1 day ago)

Actually it's a little bit of both. Some devices use an an audio stream that is encoded kind of like a normal digital audio signal where the bits go up in the encoded audio when you turn up the volume and so does the output. Other devices send a full level audio signal and send a separate control signal which tells the device to turn the volume up or down. If you push the volume button on the receiver and it shows the volume on the source (your phone) going up or down in sync with it, then it's the latter.

[–] ignirtoq@feddit.online 3 points 1 day ago (1 children)

It doesn't matter. Even if it were constantly streaming the current volume level, the energy to transmit the value "100" is the same as to transmit "5", so your phone doesn't drain any faster to constantly tell the earbuds the volume is high versus low.

[–] fizzle@quokk.au 0 points 1 day ago
[–] glimse@lemmy.world 13 points 1 day ago

This is a great question because if you're not familiar with wireless communication, it does make sense