this post was submitted on 17 Mar 2026
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[โ€“] zo0@programming.dev 74 points 6 days ago (2 children)

Just because I know what a valid IP is doesn't mean I'm not an idiot ๐Ÿ˜Ž

[โ€“] toynbee@piefed.social 16 points 6 days ago (2 children)

Let's see you write a regex for one, then we'll decide.

[โ€“] zitrone@europe.pub 2 points 1 day ago* (last edited 1 day ago) (1 children)

lemme try

(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9]?[0-9])(\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9]?[0-9])){3}

tbh i have seen the stackoverflow solutions so i kinda know what i needed to do

this is entirely typed out from brain tho

[โ€“] toynbee@piefed.social 1 points 1 day ago

I'm currently on my phone and I'm not going to try to figure out how to test regex on Graphene. Therefore I can only say: well done!

[โ€“] JasonDJ@lemmy.zip 6 points 6 days ago

Why would anyone want to do that when there are dozens on stackoverflow?

[โ€“] ulterno@programming.dev 3 points 6 days ago

That's not the probability they are looking for.