this post was submitted on 07 Dec 2025
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Advent Of Code

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An unofficial home for the advent of code community on programming.dev! Other challenges are also welcome!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

Everybody Codes is another collection of programming puzzles with seasonal events.

EC 2025

AoC 2025

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console.log('Hello World')

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Day 7: Laboratories

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[โ€“] reboot6675@sopuli.xyz 2 points 2 weeks ago

Go

Now I'm behind by 1 day, will try to catch up.

For part 2 I spent a good while thinking about it, then when I convinced myself my plan could work, struggled a bit with the implementation. But it worked in the end. Basically grid[i][j] is how many different ways you can reach a cell. Start at 1 on the S cell, then propagate the values down and keep adding up the nums when you reach cells through different paths. The answer is the sum of the nums in the last row.

spoiler

func part2() {
	// file, _ := os.Open("sample.txt")
	file, _ := os.Open("input.txt")
	defer file.Close()
	scanner := bufio.NewScanner(file)

	input := [][]rune{}

	for scanner.Scan() {
		line := []rune(scanner.Text())
		input = append(input, line)
	}

	m := len(input)
	n := len(input[0])
	grid := make([][]int, m)
	for i := range m {
		grid[i] = make([]int, n)
	}

	for i := range m {
		for j := range n {
			c := input[i][j]
			if i == 0 {
				if c == 'S' {
					grid[i][j] = 1
				}
				continue
			}
			if c == '^' {
				grid[i][j-1] += grid[i-1][j]
				grid[i][j+1] += grid[i-1][j]
			} else {
				grid[i][j] = grid[i][j] + grid[i-1][j]
			}
		}
	}

	paths := 0
	for j := range n {
		paths += grid[m-1][j]
	}

	fmt.Println(paths)
}