this post was submitted on 01 Dec 2025
47 points (100.0% liked)

Advent Of Code

1154 readers
39 users here now

An unofficial home for the advent of code community on programming.dev! Other challenges are also welcome!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

Everybody Codes is another collection of programming puzzles with seasonal events.

EC 2025

AoC 2025

Solution Threads

M T W T F S S
1 2 3 4 5 6 7
8 9 10 11 12

Rules/Guidelines

Relevant Communities

Relevant Links

Credits

Icon base by Lorc under CC BY 3.0 with modifications to add a gradient

console.log('Hello World')

founded 2 years ago
MODERATORS
 

Day 1: Secret Entrance

Megathread guidelines

  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
  • You can send code in code blocks by using three backticks, the code, and then three backticks or use something such as https://topaz.github.io/paste/ if you prefer sending it through a URL

FAQ

you are viewing a single comment's thread
view the rest of the comments
[โ€“] VegOwOtenks@lemmy.world 2 points 3 days ago

The struggled with a counting solution for a long time. I submitted with a simple enumerative solution in the end but managed to get it right after some pause time:

Haskell

Fast to Run, Stepwise Solution

{-# LANGUAGE LambdaCase #-}
{-# LANGUAGE OrPatterns #-}
module Main (main) where

import Control.Monad ( (<$!>) )
import qualified Data.List as List

main :: IO ()
main = do
  rotations <- (fmap parseRotation . init . lines) <$!> getContents
  print $ part1 rotations
  print $ part2 rotations

part2 :: [Either Int Int] -> Int
part2 rotations = let

    foldRotation (position, zeroCount) operation = case operation of
      Left y -> let
        (zeroPasses, y') = y `divMod` 100
        position' = (position - y') `mod` 100
        zeroCount' = zeroPasses + zeroCount + if position <= y' then fromEnum $ position /= 0 else 0
        in (position', zeroCount')
      Right y -> let
        (zeroPasses, y') = y `divMod` 100
        position' = (position + y') `mod` 100
        zeroCount' = zeroPasses + zeroCount + if y' + position >= 100 then 1 else 0
        in (position', zeroCount')

  in snd $ List.foldl' foldRotation (50, 0) rotations

part1 :: [Either Int Int] -> Int
part1 rotations = let
    positions = List.scanl applyRotation 50 rotations
  in List.length . filter (== 0) $ positions

applyRotation :: Int -> Either Int Int -> Int
applyRotation x = \case
  Left y -> (x - y) `mod` 100
  Right y -> (x + y) `mod` 100

parseRotation :: String -> Either Int Int
parseRotation = \case
  'R':rest -> Right $ read rest
  'L':rest -> Left $ read rest
  bad -> error $ "invalid rotation operation: " ++ bad

Fast to Code, Exhaustively Enumerating Solution

-- | Old solution enumerating all the numbers

part2' :: [Either Int Int] -> Int
part2' rotations = let
  intermediatePositions _ [] = []
  intermediatePositions x (op:ops) = case op of
    Left 0; Right 0 -> intermediatePositions x ops
    Left y -> let x' = pred x `mod` 100 in x' : intermediatePositions x' (Left (pred y) : ops)
    Right y -> let x' = succ x `mod` 100 in x' : intermediatePositions x' (Right (pred y) : ops)
  in List.length . List.filter (== 0) . intermediatePositions 50 $ rotations