C Programming Language

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Is this a limitation of scanf() or bad control flow? (piefed.blahaj.zone)

submitted 1 month ago by akunohana@piefed.blahaj.zone to c/c_lang@programming.dev

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Good afternoon! How are you all holding up today? I "accidentally" ate piece of cake at the cafe I'm currectly sitting in, even though I had promised myself not to eat sugar until next week. Fail. 😅

Don't mind the English language, since this is an excerpt from a larger piece of code.

If I enter anything other than 'Y' and 'N' using a single character, the code works as I want it to, but, naturally, if I enter anything other than 'Y' and 'N' multiple times, the if is executed the same amount of times as characters entered, which is ugly. Trying to limit this with %1c also doesn't work, since I suppose that only works with strings? Is this a limitation of scanf or rather how the logic is implemented?

Feel free to NOT provide the correct answer right away, but instead, give me the topic or the function to read up on. 😊

	char letter = '\0';  
	while(1) {  
		printf("nter the letter 'Y' or 'N': ");  
		scanf(" %c", &letter);  
		if (letter != 'Y' && letter != 'N') { //"broken" because multicharacter input executes this condition that many times.  
			printf("You have to enter 'Y' or 'N'! You have entered %c!\nE", letter);  
		}  
		else { break; }  
	}  
	printf("Good job! You have entered: %c.\n", letter);

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[–] iusemybrain@sh.itjust.works 1 points 1 week ago

I would do the loop instead the if condition, where letter != 'Y' or 'N' generally speaking, using while(1) for x86_64 programming is bad practice, specific cases like embedded system design is where it's more commonly used.