this post was submitted on 05 Dec 2025
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Advent Of Code

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An unofficial home for the advent of code community on programming.dev! Other challenges are also welcome!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

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Day 5: Cafeteria

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[โ€“] strlcpy@lemmy.sdf.org 2 points 2 weeks ago* (last edited 2 weeks ago)

C

Repo

Sweet one. Glad the merge could be done with one n^2^/2 scan and no sorting or moving, which will make the assembly port a bit easier. Speaking of which, I'm still at day 3 there, fighting not the puzzles but the 64K .COM file limit!

Code

#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#include <assert.h>

#define MR	256

#define MIN(a,b)	((a)<(b)?(a):(b))
#define MAX(a,b)	((a)>(b)?(a):(b))

struct range { uint64_t lo, hi; };

static struct range rs[MR];
static int nrs;

int
main()
{
	uint64_t p1=0,p2=0, val;
	int i,j;
	char buf[64];

        for (; fgets(buf, sizeof(buf), stdin); nrs++) {
                assert(nrs < MR);
                if (sscanf(buf, "%lu-%lu", &rs[nrs].lo, &rs[nrs].hi) != 2)
                        break;
        }

	for (i=0; i<nrs-1; i++)
	for (j=i+1; j<nrs; j++)
		if (rs[i].lo <= rs[j].hi && rs[i].hi >= rs[j].lo) {
			rs[j].lo = MIN(rs[i].lo, rs[j].lo);
			rs[j].hi = MAX(rs[i].hi, rs[j].hi);
			rs[i].lo = rs[i].hi = 0;
		}

	while (scanf("%lu", &val) == 1)
		for (i=0; i<nrs; i++)
			if (val >= rs[i].lo && val <= rs[i].hi)
				{ p1++; break; }
	
	for (i=0; i<nrs; i++)
		if (rs[i].lo)
			p2 += rs[i].hi - rs[i].lo + 1;
	
	printf("05: %lu %lu\n", p1, p2);
}