Advent Of Code

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An unofficial home for the advent of code community on programming.dev! Other challenges are also welcome!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

Everybody Codes is another collection of programming puzzles with seasonal events.

AoC 2025

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🖥️ - 2024 DAY 17 SOLUTIONS - 🖥️ (programming.dev)

submitted 1 year ago by CameronDev@programming.dev to c/advent_of_code@programming.dev

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Day 17: Chronospatial Computer

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[–] SteveDinn@lemmy.ca 3 points 1 year ago (1 children)

I'm confused reading the buildQuine() method. It reads to me that when you call it from the top level with top = true, A0 will be set to 0, and then when we get to the 0 to 8 loop, the 'A' register will be 0 * 8 + 0 for the first iteration, and then recurse with top = false, but with a0 still ending up 0, causing infinite recursion.

Am I missing something?

I got it to work with a check that avoids the recursion if the last state's A register value is the same as the new state's value.

[–] mykl@lemmy.world 3 points 1 year ago

Oh, good catch. That's certainly the case if an initial value of 0 correctly generates the required value of the quine. As I'd already started running some code against the live data that's what I tested against, and so it's only when I just tested it against the example data that I saw the problem.

I have changed the for-loop to read for (var a in (top ? 1 : 0).to(8)) for maximum terseness :-)

That still works for the example and my live data, and I don't think there should be a valid solution that relies on the first triplet being 0. Thanks for your reply!