this post was submitted on 11 Dec 2025
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Advent Of Code

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An unofficial home for the advent of code community on programming.dev! Other challenges are also welcome!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

Everybody Codes is another collection of programming puzzles with seasonal events.

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Day 11: Reactor

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[–] mykl@lemmy.world 2 points 1 week ago* (last edited 1 week ago) (4 children)

Uiua

If it's stupid but it works...

My dirty hackI broke the maze into SVR>FFT>DAC>OUT and SVR>DAC>FFT>OUT, realised that the latter was taking a suspiciously long time, so submitted just the answer from the former --> success!

link (You'll need to up the execution limit)

# AOC2025day11 - mazes.
# Uncomment for Part 1
D ← "aaa: you hhh\nyou: bbb ccc\nbbb: ddd eee\nccc: ddd eee fff\nddd: ggg\neee: out\nfff: out\nggg: out\nhhh: ccc fff iii\niii: out"
# Uncomment for Part 2
# D ← "svr: aaa bbb\naaa: fft\nfft: ccc\nbbb: tty\ntty: ccc\nccc: ddd eee\nddd: hub\nhub: fff\neee: dac\ndac: fff\nfff: ggg hhh\nggg: out\nhhh: out"
# D      ← &fras "randomAOC/AOC2025day11.txt"
Tabs   ← ⊜(⊙□°⊂⊜∘¬⊸∊": ")⊸≠@\nD
Nexts  ← ⍣(°□⊡˜⨂⊙Tabs|[])
Part₁  ← ⊙◌⧻path(˙≠°⊏Nexts|≍"out")"you"

Part₂ ← (
  ⊙◌⧻path(˙≠°⊏Nexts|≍"fft")"svr"
  ⊙◌⧻path(˙≠°⊏Nexts|≍"dac")"fft"
  ⊙◌⧻path(˙≠°⊏Nexts|≍"out")"dac"
  ××
)
# Only one will be right for the test data, depending on dataset.
⊃Part₁ Part₂
[–] CameronDev@programming.dev 2 points 1 week ago (3 children)

I also broke up the pathing, mine has zero paths from DAC to FFT. If I join DAC directly FFT, i get a stackoverflow, so maybe its intentional.

[–] EnEnCode@programming.dev 2 points 1 week ago (1 children)

If you can explain why it works, not calculating half the paths isn't a hack—it's an optimization. ;)

[–] CameronDev@programming.dev 1 points 1 week ago

I think the hack was just skipping the entire second set of paths, but yeah, splitting was an nice optimisation. Might not scale as well if that path had to hit multiple intermediate nodes though.

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